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Why do C and C++ allow the expression (int) + 4*5;



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!Cast int to enum in C#What are the differences between a pointer variable and a reference variable in C++?The Definitive C++ Book Guide and ListDo I cast the result of malloc?Why is “using namespace std” considered bad practice?What is the “-->” operator in C++?C++11 introduced a standardized memory model. What does it mean? And how is it going to affect C++ programming?Why are elementwise additions much faster in separate loops than in a combined loop?Why don't Java's +=, -=, *=, /= compound assignment operators require casting?Why is it faster to process a sorted array than an unsorted array?



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19















(int) + 4*5;


Why is this possible? (tried with g++ and gcc.)










share|improve this question









New contributor




Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • Even this is valid it is not a good idea to do that in a program because yes this is quite disturbing ^^

    – bruno
    9 hours ago







  • 3





    same as (int)-4*5

    – P__J__
    8 hours ago











  • Though "(int) (+4.0 * 5.0)" might make more sense, or "(double) (+4 * 5)". But this has me totally puzzled. Why would you write a line of code like this, without assigning the result, and why the heck does the compiler not at least issue a warning?/

    – jamesqf
    7 hours ago






  • 1





    @jamesqf I know that it dosn't make sense, but I want to know why this is possible and for this is sense not needed.

    – Ernest Bredar
    6 hours ago






  • 4





    There is a useful tool called cppinsights that helps to understand how the code looks from the compiler frontend perspective. It also has an online version, you can see what it tells about your example (the same 'parenthesization' as the answers your were given)

    – Nikita Kniazev
    2 hours ago

















19















(int) + 4*5;


Why is this possible? (tried with g++ and gcc.)










share|improve this question









New contributor




Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Even this is valid it is not a good idea to do that in a program because yes this is quite disturbing ^^

    – bruno
    9 hours ago







  • 3





    same as (int)-4*5

    – P__J__
    8 hours ago











  • Though "(int) (+4.0 * 5.0)" might make more sense, or "(double) (+4 * 5)". But this has me totally puzzled. Why would you write a line of code like this, without assigning the result, and why the heck does the compiler not at least issue a warning?/

    – jamesqf
    7 hours ago






  • 1





    @jamesqf I know that it dosn't make sense, but I want to know why this is possible and for this is sense not needed.

    – Ernest Bredar
    6 hours ago






  • 4





    There is a useful tool called cppinsights that helps to understand how the code looks from the compiler frontend perspective. It also has an online version, you can see what it tells about your example (the same 'parenthesization' as the answers your were given)

    – Nikita Kniazev
    2 hours ago













19












19








19








(int) + 4*5;


Why is this possible? (tried with g++ and gcc.)










share|improve this question









New contributor




Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












(int) + 4*5;


Why is this possible? (tried with g++ and gcc.)







c++ c casting language-lawyer






share|improve this question









New contributor




Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 24 mins ago









Dai

74.6k15120209




74.6k15120209






New contributor




Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 9 hours ago









Ernest BredarErnest Bredar

1135




1135




New contributor




Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Ernest Bredar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Even this is valid it is not a good idea to do that in a program because yes this is quite disturbing ^^

    – bruno
    9 hours ago







  • 3





    same as (int)-4*5

    – P__J__
    8 hours ago











  • Though "(int) (+4.0 * 5.0)" might make more sense, or "(double) (+4 * 5)". But this has me totally puzzled. Why would you write a line of code like this, without assigning the result, and why the heck does the compiler not at least issue a warning?/

    – jamesqf
    7 hours ago






  • 1





    @jamesqf I know that it dosn't make sense, but I want to know why this is possible and for this is sense not needed.

    – Ernest Bredar
    6 hours ago






  • 4





    There is a useful tool called cppinsights that helps to understand how the code looks from the compiler frontend perspective. It also has an online version, you can see what it tells about your example (the same 'parenthesization' as the answers your were given)

    – Nikita Kniazev
    2 hours ago

















  • Even this is valid it is not a good idea to do that in a program because yes this is quite disturbing ^^

    – bruno
    9 hours ago







  • 3





    same as (int)-4*5

    – P__J__
    8 hours ago











  • Though "(int) (+4.0 * 5.0)" might make more sense, or "(double) (+4 * 5)". But this has me totally puzzled. Why would you write a line of code like this, without assigning the result, and why the heck does the compiler not at least issue a warning?/

    – jamesqf
    7 hours ago






  • 1





    @jamesqf I know that it dosn't make sense, but I want to know why this is possible and for this is sense not needed.

    – Ernest Bredar
    6 hours ago






  • 4





    There is a useful tool called cppinsights that helps to understand how the code looks from the compiler frontend perspective. It also has an online version, you can see what it tells about your example (the same 'parenthesization' as the answers your were given)

    – Nikita Kniazev
    2 hours ago
















Even this is valid it is not a good idea to do that in a program because yes this is quite disturbing ^^

– bruno
9 hours ago






Even this is valid it is not a good idea to do that in a program because yes this is quite disturbing ^^

– bruno
9 hours ago





3




3





same as (int)-4*5

– P__J__
8 hours ago





same as (int)-4*5

– P__J__
8 hours ago













Though "(int) (+4.0 * 5.0)" might make more sense, or "(double) (+4 * 5)". But this has me totally puzzled. Why would you write a line of code like this, without assigning the result, and why the heck does the compiler not at least issue a warning?/

– jamesqf
7 hours ago





Though "(int) (+4.0 * 5.0)" might make more sense, or "(double) (+4 * 5)". But this has me totally puzzled. Why would you write a line of code like this, without assigning the result, and why the heck does the compiler not at least issue a warning?/

– jamesqf
7 hours ago




1




1





@jamesqf I know that it dosn't make sense, but I want to know why this is possible and for this is sense not needed.

– Ernest Bredar
6 hours ago





@jamesqf I know that it dosn't make sense, but I want to know why this is possible and for this is sense not needed.

– Ernest Bredar
6 hours ago




4




4





There is a useful tool called cppinsights that helps to understand how the code looks from the compiler frontend perspective. It also has an online version, you can see what it tells about your example (the same 'parenthesization' as the answers your were given)

– Nikita Kniazev
2 hours ago





There is a useful tool called cppinsights that helps to understand how the code looks from the compiler frontend perspective. It also has an online version, you can see what it tells about your example (the same 'parenthesization' as the answers your were given)

– Nikita Kniazev
2 hours ago












2 Answers
2






active

oldest

votes


















34














The + here is unary + operator, not the binary addition operator. There's no addition happening here.



Also, the syntax (int) is used for typecasting.



You can re-read that statement as



(int) (+ 4) * 5; 


which is parsed as



((int) (+ 4)) * (5); 


which says,



  • Make the operand +4

  • typecasted to an int

  • multiply with operand 5

This is similar to (int) (- 4) * (5);, where the usage of the unary operator is more familiar.



In your case, the unary + and the cast to int - both are redundant.






share|improve this answer

























  • "Casting", not "typecasting". Typecasting is something that happens to actors.

    – Keith Thompson
    15 mins ago


















22














This is interpreted as ((int)(+4)) * 5. That is, an expression +4 (a unary plus operator applied to a literal 4), cast to type int with a C-style cast, and the result multiplied by 5.






share|improve this answer























    Your Answer






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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    34














    The + here is unary + operator, not the binary addition operator. There's no addition happening here.



    Also, the syntax (int) is used for typecasting.



    You can re-read that statement as



    (int) (+ 4) * 5; 


    which is parsed as



    ((int) (+ 4)) * (5); 


    which says,



    • Make the operand +4

    • typecasted to an int

    • multiply with operand 5

    This is similar to (int) (- 4) * (5);, where the usage of the unary operator is more familiar.



    In your case, the unary + and the cast to int - both are redundant.






    share|improve this answer

























    • "Casting", not "typecasting". Typecasting is something that happens to actors.

      – Keith Thompson
      15 mins ago















    34














    The + here is unary + operator, not the binary addition operator. There's no addition happening here.



    Also, the syntax (int) is used for typecasting.



    You can re-read that statement as



    (int) (+ 4) * 5; 


    which is parsed as



    ((int) (+ 4)) * (5); 


    which says,



    • Make the operand +4

    • typecasted to an int

    • multiply with operand 5

    This is similar to (int) (- 4) * (5);, where the usage of the unary operator is more familiar.



    In your case, the unary + and the cast to int - both are redundant.






    share|improve this answer

























    • "Casting", not "typecasting". Typecasting is something that happens to actors.

      – Keith Thompson
      15 mins ago













    34












    34








    34







    The + here is unary + operator, not the binary addition operator. There's no addition happening here.



    Also, the syntax (int) is used for typecasting.



    You can re-read that statement as



    (int) (+ 4) * 5; 


    which is parsed as



    ((int) (+ 4)) * (5); 


    which says,



    • Make the operand +4

    • typecasted to an int

    • multiply with operand 5

    This is similar to (int) (- 4) * (5);, where the usage of the unary operator is more familiar.



    In your case, the unary + and the cast to int - both are redundant.






    share|improve this answer















    The + here is unary + operator, not the binary addition operator. There's no addition happening here.



    Also, the syntax (int) is used for typecasting.



    You can re-read that statement as



    (int) (+ 4) * 5; 


    which is parsed as



    ((int) (+ 4)) * (5); 


    which says,



    • Make the operand +4

    • typecasted to an int

    • multiply with operand 5

    This is similar to (int) (- 4) * (5);, where the usage of the unary operator is more familiar.



    In your case, the unary + and the cast to int - both are redundant.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 5 hours ago









    Dancrumb

    18.2k448103




    18.2k448103










    answered 9 hours ago









    Sourav GhoshSourav Ghosh

    112k15136194




    112k15136194












    • "Casting", not "typecasting". Typecasting is something that happens to actors.

      – Keith Thompson
      15 mins ago

















    • "Casting", not "typecasting". Typecasting is something that happens to actors.

      – Keith Thompson
      15 mins ago
















    "Casting", not "typecasting". Typecasting is something that happens to actors.

    – Keith Thompson
    15 mins ago





    "Casting", not "typecasting". Typecasting is something that happens to actors.

    – Keith Thompson
    15 mins ago













    22














    This is interpreted as ((int)(+4)) * 5. That is, an expression +4 (a unary plus operator applied to a literal 4), cast to type int with a C-style cast, and the result multiplied by 5.






    share|improve this answer



























      22














      This is interpreted as ((int)(+4)) * 5. That is, an expression +4 (a unary plus operator applied to a literal 4), cast to type int with a C-style cast, and the result multiplied by 5.






      share|improve this answer

























        22












        22








        22







        This is interpreted as ((int)(+4)) * 5. That is, an expression +4 (a unary plus operator applied to a literal 4), cast to type int with a C-style cast, and the result multiplied by 5.






        share|improve this answer













        This is interpreted as ((int)(+4)) * 5. That is, an expression +4 (a unary plus operator applied to a literal 4), cast to type int with a C-style cast, and the result multiplied by 5.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 9 hours ago









        Igor TandetnikIgor Tandetnik

        33.4k33559




        33.4k33559




















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