Recursively updating the MLE as new observations stream inSimple MLE Question4 cases of Maximum Likelihood Estimation of Gaussian distribution parameterssimulating random samples with a given MLEFor the family of distributions, $f_theta(x) = theta x^theta-1$, what is the sufficient statistic corresponding to the monotone likelihood ratio?Prove that MLE does not depend on the dominating measureDetermining an MLEMLE of $f(xmidtheta) = theta x^theta−1e^−x^thetaI_(0,infty)(x)$Sufficient statistic when $Xsim U(theta,2 theta)$Estimating the MLE where the parameter is also the constraintTrouble with MLE

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Recursively updating the MLE as new observations stream in


Simple MLE Question4 cases of Maximum Likelihood Estimation of Gaussian distribution parameterssimulating random samples with a given MLEFor the family of distributions, $f_theta(x) = theta x^theta-1$, what is the sufficient statistic corresponding to the monotone likelihood ratio?Prove that MLE does not depend on the dominating measureDetermining an MLEMLE of $f(xmidtheta) = theta x^theta−1e^−x^thetaI_(0,infty)(x)$Sufficient statistic when $Xsim U(theta,2 theta)$Estimating the MLE where the parameter is also the constraintTrouble with MLE













3












$begingroup$


General Question



Say we have iid data $x_1$, $x_2$, ... $sim f(x,|,boldsymboltheta)$ streaming in. We want to recursively compute the maximum likelihood estimate of $boldsymboltheta$. That is, having computed
$$hatboldsymboltheta_n-1=undersetboldsymbolthetainmathbbR^pargmaxprod_i=1^n-1f(x_i,|,boldsymboltheta),$$
we observe a new $x_n$, and wish to somehow incrementally update our estimate
$$hatboldsymboltheta_n-1,,x_n to hatboldsymboltheta_n$$
without having to start from scratch. Are there generic algorithms for this?



Toy Example



If $x_1$, $x_2$, ... $sim N(x,|,mu, 1)$, then
$$hatmu_n-1 = frac1n-1sumlimits_i=1^n-1x_iquadtextandquadhatmu_n = frac1nsumlimits_i=1^nx_i,$$
so
$$hatmu_n=frac1nleft[(n-1)hatmu_n-1 + x_nright].$$










share|cite|improve this question











$endgroup$











  • $begingroup$
    Awesome question!
    $endgroup$
    – dlnB
    2 hours ago










  • $begingroup$
    Don't forget the inverse of this problem: updating the estimator as old observations are deleted.
    $endgroup$
    – Hong Ooi
    2 mins ago















3












$begingroup$


General Question



Say we have iid data $x_1$, $x_2$, ... $sim f(x,|,boldsymboltheta)$ streaming in. We want to recursively compute the maximum likelihood estimate of $boldsymboltheta$. That is, having computed
$$hatboldsymboltheta_n-1=undersetboldsymbolthetainmathbbR^pargmaxprod_i=1^n-1f(x_i,|,boldsymboltheta),$$
we observe a new $x_n$, and wish to somehow incrementally update our estimate
$$hatboldsymboltheta_n-1,,x_n to hatboldsymboltheta_n$$
without having to start from scratch. Are there generic algorithms for this?



Toy Example



If $x_1$, $x_2$, ... $sim N(x,|,mu, 1)$, then
$$hatmu_n-1 = frac1n-1sumlimits_i=1^n-1x_iquadtextandquadhatmu_n = frac1nsumlimits_i=1^nx_i,$$
so
$$hatmu_n=frac1nleft[(n-1)hatmu_n-1 + x_nright].$$










share|cite|improve this question











$endgroup$











  • $begingroup$
    Awesome question!
    $endgroup$
    – dlnB
    2 hours ago










  • $begingroup$
    Don't forget the inverse of this problem: updating the estimator as old observations are deleted.
    $endgroup$
    – Hong Ooi
    2 mins ago













3












3








3


2



$begingroup$


General Question



Say we have iid data $x_1$, $x_2$, ... $sim f(x,|,boldsymboltheta)$ streaming in. We want to recursively compute the maximum likelihood estimate of $boldsymboltheta$. That is, having computed
$$hatboldsymboltheta_n-1=undersetboldsymbolthetainmathbbR^pargmaxprod_i=1^n-1f(x_i,|,boldsymboltheta),$$
we observe a new $x_n$, and wish to somehow incrementally update our estimate
$$hatboldsymboltheta_n-1,,x_n to hatboldsymboltheta_n$$
without having to start from scratch. Are there generic algorithms for this?



Toy Example



If $x_1$, $x_2$, ... $sim N(x,|,mu, 1)$, then
$$hatmu_n-1 = frac1n-1sumlimits_i=1^n-1x_iquadtextandquadhatmu_n = frac1nsumlimits_i=1^nx_i,$$
so
$$hatmu_n=frac1nleft[(n-1)hatmu_n-1 + x_nright].$$










share|cite|improve this question











$endgroup$




General Question



Say we have iid data $x_1$, $x_2$, ... $sim f(x,|,boldsymboltheta)$ streaming in. We want to recursively compute the maximum likelihood estimate of $boldsymboltheta$. That is, having computed
$$hatboldsymboltheta_n-1=undersetboldsymbolthetainmathbbR^pargmaxprod_i=1^n-1f(x_i,|,boldsymboltheta),$$
we observe a new $x_n$, and wish to somehow incrementally update our estimate
$$hatboldsymboltheta_n-1,,x_n to hatboldsymboltheta_n$$
without having to start from scratch. Are there generic algorithms for this?



Toy Example



If $x_1$, $x_2$, ... $sim N(x,|,mu, 1)$, then
$$hatmu_n-1 = frac1n-1sumlimits_i=1^n-1x_iquadtextandquadhatmu_n = frac1nsumlimits_i=1^nx_i,$$
so
$$hatmu_n=frac1nleft[(n-1)hatmu_n-1 + x_nright].$$







maximum-likelihood online






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 1 hour ago







bamts

















asked 2 hours ago









bamtsbamts

753312




753312











  • $begingroup$
    Awesome question!
    $endgroup$
    – dlnB
    2 hours ago










  • $begingroup$
    Don't forget the inverse of this problem: updating the estimator as old observations are deleted.
    $endgroup$
    – Hong Ooi
    2 mins ago
















  • $begingroup$
    Awesome question!
    $endgroup$
    – dlnB
    2 hours ago










  • $begingroup$
    Don't forget the inverse of this problem: updating the estimator as old observations are deleted.
    $endgroup$
    – Hong Ooi
    2 mins ago















$begingroup$
Awesome question!
$endgroup$
– dlnB
2 hours ago




$begingroup$
Awesome question!
$endgroup$
– dlnB
2 hours ago












$begingroup$
Don't forget the inverse of this problem: updating the estimator as old observations are deleted.
$endgroup$
– Hong Ooi
2 mins ago




$begingroup$
Don't forget the inverse of this problem: updating the estimator as old observations are deleted.
$endgroup$
– Hong Ooi
2 mins ago










2 Answers
2






active

oldest

votes


















4












$begingroup$

See the concept of sufficiency and in particular, minimal sufficient statistics. In many cases you need the whole sample to compute the estimate at a given sample size, with no trivial way to update from a sample one size smaller (i.e. there's no convenient general result).



If the distribution is exponential family (and in some other cases besides; the uniform is a neat example) there's a nice sufficient statistic that can in many cases be updated in the manner you seek (i.e. with a number of commonly used distributions there would be a fast update).



One example I'm not aware of any direct way to either calculate or update is the estimate for the location of the Cauchy distribution (e.g. with unit scale, to make the problem a simple one-parameter problem). There may be a faster update, however, that I simply haven't noticed - I can't say I've really done more than glance at it for considering the updating case.



On the other hand, with MLEs that are obtained via numerical optimization methods, the previous estimate would in many cases be a great starting point, since typically the previous estimate would be very close to the updated estimate; in that sense at least, rapid updating should often be possible. Even this isn't the general case, though -- with multimodal likelihood functions (again, see the Cauchy for an example), a new observation might lead to the highest mode being some distance from the previous one (even if the locations of each of the biggest few modes didn't shift much, which one is highest could well change).






share|cite|improve this answer











$endgroup$




















    0












    $begingroup$

    In machine learning, this is referred to as online learning.



    As @Glen_b pointed out, there are special cases in which the MLE can be updated without needing to access all the previous data. As he also points out, I don't believe there's a generic solution for finding the MLE.



    A fairly generic approach for finding the approximate solution is to use something like stochastic gradient descent. In this case, as each observation comes in, we compute the gradient with respect to this individual observation and move the parameter values a very small amount in this direction. Under certain conditions, we can show that this will converge to a neighborhood of the MLE with high probability; the neighborhood is tighter and tighter as we reduce the step size, but more data is required for convergence. However, these stochastic methods in general require much more fiddling to obtain good performance than, say, closed form updates.






    share|cite|improve this answer









    $endgroup$












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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      4












      $begingroup$

      See the concept of sufficiency and in particular, minimal sufficient statistics. In many cases you need the whole sample to compute the estimate at a given sample size, with no trivial way to update from a sample one size smaller (i.e. there's no convenient general result).



      If the distribution is exponential family (and in some other cases besides; the uniform is a neat example) there's a nice sufficient statistic that can in many cases be updated in the manner you seek (i.e. with a number of commonly used distributions there would be a fast update).



      One example I'm not aware of any direct way to either calculate or update is the estimate for the location of the Cauchy distribution (e.g. with unit scale, to make the problem a simple one-parameter problem). There may be a faster update, however, that I simply haven't noticed - I can't say I've really done more than glance at it for considering the updating case.



      On the other hand, with MLEs that are obtained via numerical optimization methods, the previous estimate would in many cases be a great starting point, since typically the previous estimate would be very close to the updated estimate; in that sense at least, rapid updating should often be possible. Even this isn't the general case, though -- with multimodal likelihood functions (again, see the Cauchy for an example), a new observation might lead to the highest mode being some distance from the previous one (even if the locations of each of the biggest few modes didn't shift much, which one is highest could well change).






      share|cite|improve this answer











      $endgroup$

















        4












        $begingroup$

        See the concept of sufficiency and in particular, minimal sufficient statistics. In many cases you need the whole sample to compute the estimate at a given sample size, with no trivial way to update from a sample one size smaller (i.e. there's no convenient general result).



        If the distribution is exponential family (and in some other cases besides; the uniform is a neat example) there's a nice sufficient statistic that can in many cases be updated in the manner you seek (i.e. with a number of commonly used distributions there would be a fast update).



        One example I'm not aware of any direct way to either calculate or update is the estimate for the location of the Cauchy distribution (e.g. with unit scale, to make the problem a simple one-parameter problem). There may be a faster update, however, that I simply haven't noticed - I can't say I've really done more than glance at it for considering the updating case.



        On the other hand, with MLEs that are obtained via numerical optimization methods, the previous estimate would in many cases be a great starting point, since typically the previous estimate would be very close to the updated estimate; in that sense at least, rapid updating should often be possible. Even this isn't the general case, though -- with multimodal likelihood functions (again, see the Cauchy for an example), a new observation might lead to the highest mode being some distance from the previous one (even if the locations of each of the biggest few modes didn't shift much, which one is highest could well change).






        share|cite|improve this answer











        $endgroup$















          4












          4








          4





          $begingroup$

          See the concept of sufficiency and in particular, minimal sufficient statistics. In many cases you need the whole sample to compute the estimate at a given sample size, with no trivial way to update from a sample one size smaller (i.e. there's no convenient general result).



          If the distribution is exponential family (and in some other cases besides; the uniform is a neat example) there's a nice sufficient statistic that can in many cases be updated in the manner you seek (i.e. with a number of commonly used distributions there would be a fast update).



          One example I'm not aware of any direct way to either calculate or update is the estimate for the location of the Cauchy distribution (e.g. with unit scale, to make the problem a simple one-parameter problem). There may be a faster update, however, that I simply haven't noticed - I can't say I've really done more than glance at it for considering the updating case.



          On the other hand, with MLEs that are obtained via numerical optimization methods, the previous estimate would in many cases be a great starting point, since typically the previous estimate would be very close to the updated estimate; in that sense at least, rapid updating should often be possible. Even this isn't the general case, though -- with multimodal likelihood functions (again, see the Cauchy for an example), a new observation might lead to the highest mode being some distance from the previous one (even if the locations of each of the biggest few modes didn't shift much, which one is highest could well change).






          share|cite|improve this answer











          $endgroup$



          See the concept of sufficiency and in particular, minimal sufficient statistics. In many cases you need the whole sample to compute the estimate at a given sample size, with no trivial way to update from a sample one size smaller (i.e. there's no convenient general result).



          If the distribution is exponential family (and in some other cases besides; the uniform is a neat example) there's a nice sufficient statistic that can in many cases be updated in the manner you seek (i.e. with a number of commonly used distributions there would be a fast update).



          One example I'm not aware of any direct way to either calculate or update is the estimate for the location of the Cauchy distribution (e.g. with unit scale, to make the problem a simple one-parameter problem). There may be a faster update, however, that I simply haven't noticed - I can't say I've really done more than glance at it for considering the updating case.



          On the other hand, with MLEs that are obtained via numerical optimization methods, the previous estimate would in many cases be a great starting point, since typically the previous estimate would be very close to the updated estimate; in that sense at least, rapid updating should often be possible. Even this isn't the general case, though -- with multimodal likelihood functions (again, see the Cauchy for an example), a new observation might lead to the highest mode being some distance from the previous one (even if the locations of each of the biggest few modes didn't shift much, which one is highest could well change).







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited 58 mins ago

























          answered 1 hour ago









          Glen_bGlen_b

          214k22414764




          214k22414764























              0












              $begingroup$

              In machine learning, this is referred to as online learning.



              As @Glen_b pointed out, there are special cases in which the MLE can be updated without needing to access all the previous data. As he also points out, I don't believe there's a generic solution for finding the MLE.



              A fairly generic approach for finding the approximate solution is to use something like stochastic gradient descent. In this case, as each observation comes in, we compute the gradient with respect to this individual observation and move the parameter values a very small amount in this direction. Under certain conditions, we can show that this will converge to a neighborhood of the MLE with high probability; the neighborhood is tighter and tighter as we reduce the step size, but more data is required for convergence. However, these stochastic methods in general require much more fiddling to obtain good performance than, say, closed form updates.






              share|cite|improve this answer









              $endgroup$

















                0












                $begingroup$

                In machine learning, this is referred to as online learning.



                As @Glen_b pointed out, there are special cases in which the MLE can be updated without needing to access all the previous data. As he also points out, I don't believe there's a generic solution for finding the MLE.



                A fairly generic approach for finding the approximate solution is to use something like stochastic gradient descent. In this case, as each observation comes in, we compute the gradient with respect to this individual observation and move the parameter values a very small amount in this direction. Under certain conditions, we can show that this will converge to a neighborhood of the MLE with high probability; the neighborhood is tighter and tighter as we reduce the step size, but more data is required for convergence. However, these stochastic methods in general require much more fiddling to obtain good performance than, say, closed form updates.






                share|cite|improve this answer









                $endgroup$















                  0












                  0








                  0





                  $begingroup$

                  In machine learning, this is referred to as online learning.



                  As @Glen_b pointed out, there are special cases in which the MLE can be updated without needing to access all the previous data. As he also points out, I don't believe there's a generic solution for finding the MLE.



                  A fairly generic approach for finding the approximate solution is to use something like stochastic gradient descent. In this case, as each observation comes in, we compute the gradient with respect to this individual observation and move the parameter values a very small amount in this direction. Under certain conditions, we can show that this will converge to a neighborhood of the MLE with high probability; the neighborhood is tighter and tighter as we reduce the step size, but more data is required for convergence. However, these stochastic methods in general require much more fiddling to obtain good performance than, say, closed form updates.






                  share|cite|improve this answer









                  $endgroup$



                  In machine learning, this is referred to as online learning.



                  As @Glen_b pointed out, there are special cases in which the MLE can be updated without needing to access all the previous data. As he also points out, I don't believe there's a generic solution for finding the MLE.



                  A fairly generic approach for finding the approximate solution is to use something like stochastic gradient descent. In this case, as each observation comes in, we compute the gradient with respect to this individual observation and move the parameter values a very small amount in this direction. Under certain conditions, we can show that this will converge to a neighborhood of the MLE with high probability; the neighborhood is tighter and tighter as we reduce the step size, but more data is required for convergence. However, these stochastic methods in general require much more fiddling to obtain good performance than, say, closed form updates.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 14 mins ago









                  Cliff ABCliff AB

                  13.6k12567




                  13.6k12567



























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