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Spacing after equals sign in align
Sums and differences spanning multiple linesspacing after “equals” sign in align environmentLyX Spacing after = sign in alignUsing gather and align togetherAlign multiline RHSHow can I make a single-aligned row under two double-aligned rows in an equation?Left aligning equations without align characterIs there a way to put two labelled equations into one beginequation and align both of them at the beginning?Align multiple equationsAlign different equations on different equal signsspacing after “equals” sign in align environmentAlign equations within one lineTrying to align the equations and labelling
I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align
environment. I have a long expression which has to be split up in multiple rows. The alignment character &
appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?
Ideally, I would like to have the second row from the first equation, and the first row from the second equation.
documentclassarticle
usepackageamsmath
begindocument
beginalign % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^-t
endalign
beginalign % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^-t
endalign
enddocument
math-mode align
add a comment |
I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align
environment. I have a long expression which has to be split up in multiple rows. The alignment character &
appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?
Ideally, I would like to have the second row from the first equation, and the first row from the second equation.
documentclassarticle
usepackageamsmath
begindocument
beginalign % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^-t
endalign
beginalign % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^-t
endalign
enddocument
math-mode align
2
Welcome to TeX.SE! To get the correct spacing around the=
sign, one must write&=
rather than=&
.
– Mico
Nov 17 '14 at 13:50
add a comment |
I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align
environment. I have a long expression which has to be split up in multiple rows. The alignment character &
appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?
Ideally, I would like to have the second row from the first equation, and the first row from the second equation.
documentclassarticle
usepackageamsmath
begindocument
beginalign % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^-t
endalign
beginalign % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^-t
endalign
enddocument
math-mode align
I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align
environment. I have a long expression which has to be split up in multiple rows. The alignment character &
appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?
Ideally, I would like to have the second row from the first equation, and the first row from the second equation.
documentclassarticle
usepackageamsmath
begindocument
beginalign % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^-t
endalign
beginalign % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^-t
endalign
enddocument
math-mode align
math-mode align
asked Nov 17 '14 at 13:44
Martin LMartin L
16316
16316
2
Welcome to TeX.SE! To get the correct spacing around the=
sign, one must write&=
rather than=&
.
– Mico
Nov 17 '14 at 13:50
add a comment |
2
Welcome to TeX.SE! To get the correct spacing around the=
sign, one must write&=
rather than=&
.
– Mico
Nov 17 '14 at 13:50
2
2
Welcome to TeX.SE! To get the correct spacing around the
=
sign, one must write &=
rather than =&
.– Mico
Nov 17 '14 at 13:50
Welcome to TeX.SE! To get the correct spacing around the
=
sign, one must write &=
rather than =&
.– Mico
Nov 17 '14 at 13:50
add a comment |
5 Answers
5
active
oldest
votes
Put the ampersand before the equals sign. Then use quad
to create the indentation in the second row.
documentclassarticle
usepackageamsmath
begindocument
beginalign
2 cosh t &= e^t \
&quad+ e^-t
endalign
enddocument
You can also use hspace
if you want a different length for the indentation.
3
Wouldn'tbeginalign 2 cosh t &= e^t \ &phantom= + e^-t endalign
be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.
– Niel de Beaudrap
Nov 17 '14 at 17:21
I'd say it's a matter of taste.
– Ian Thompson
Nov 18 '14 at 8:08
add a comment |
I wouldn't try aligning the plus with e^t
, but if you insist, here's how.
documentclassarticle
usepackageamsmath
begindocument
noindent
The plus is flush with $e^t$ (I wouldn't recommend it):
beginalign
2cosh t =& e^t \
& negmedspace+ e^-t
endalign
The plus is moved right (better):
beginalign
2cosh t &= e^t \
&qquad+ e^-t
endalign
enddocument
With negmedspace
we kill the space at the left of the binary operation symbol.
However, align
is the wrong tool here:
documentclassarticle
usepackageamsmath
begindocument
beginequation
beginsplit
2cosh t &= e^t \
&qquad + e^-t
endsplit
endequation
add a comment |
Suppose you wish to ensure that the two instances of e
are aligned vertically, while respecting the fact that a binary operator (+
) precedes the e
in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom
("horizonal phantom") statements. The one in the first row mimics the +
symbol (a binary operator) from the second row, and the hphantom
statement in the second row mimics the =
symbol (a relational operator) from the first row. The pairs are there to help TeX figure out which type of operator applies.
documentclassarticle
usepackageamsmath
setlengthtextwidth3in %% just for this example
begindocument
beginalign
2cosh t &= phantom+ mathrme^t \
&phantom= + mathrme^-t
endalign
enddocument
add a comment |
You have placed the &
wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom
to indent the expression in the second line to get the correct alignment. (Notice the before
=
.)
documentclassarticle
usepackageamsmath
begindocument
beginalign
2cosh t
&= e^t \
&hphantom= + e^-t
endalign
enddocument
1
It is not wrong, one just have to be a bit more careful. Besides ` = &` is a lot short to type than&hphantom=
;-)
– daleif
Nov 17 '14 at 15:19
@daleif Good point. The reason why I usedhphantom
is that it's more 'universal'.
– Svend Tveskæg
Nov 17 '14 at 16:33
add a comment |
Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.
LaTeX encloses relation symbols with thick spaces ;
, and binary symbols with medium spaces :
. The symbols =
and +
in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:
2 cosh t & ; mathord= ; e^t \
& ; phantom= ; mathord+ : e^-t
A practical incarnation of the above is (see page 36 of l2kurz.pdf):
2 cosh t & = e^t \
& mathrelphantom= negmedspace + e^-t
First, we redeem the relation status of =
robbed by the phantom
command. Second, we insert an empty group telling LaTeX to interpret
+
as a binary rather than a prefix symbol; but this creates a spurious medium space :
that needs to be compensated.
New contributor
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Put the ampersand before the equals sign. Then use quad
to create the indentation in the second row.
documentclassarticle
usepackageamsmath
begindocument
beginalign
2 cosh t &= e^t \
&quad+ e^-t
endalign
enddocument
You can also use hspace
if you want a different length for the indentation.
3
Wouldn'tbeginalign 2 cosh t &= e^t \ &phantom= + e^-t endalign
be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.
– Niel de Beaudrap
Nov 17 '14 at 17:21
I'd say it's a matter of taste.
– Ian Thompson
Nov 18 '14 at 8:08
add a comment |
Put the ampersand before the equals sign. Then use quad
to create the indentation in the second row.
documentclassarticle
usepackageamsmath
begindocument
beginalign
2 cosh t &= e^t \
&quad+ e^-t
endalign
enddocument
You can also use hspace
if you want a different length for the indentation.
3
Wouldn'tbeginalign 2 cosh t &= e^t \ &phantom= + e^-t endalign
be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.
– Niel de Beaudrap
Nov 17 '14 at 17:21
I'd say it's a matter of taste.
– Ian Thompson
Nov 18 '14 at 8:08
add a comment |
Put the ampersand before the equals sign. Then use quad
to create the indentation in the second row.
documentclassarticle
usepackageamsmath
begindocument
beginalign
2 cosh t &= e^t \
&quad+ e^-t
endalign
enddocument
You can also use hspace
if you want a different length for the indentation.
Put the ampersand before the equals sign. Then use quad
to create the indentation in the second row.
documentclassarticle
usepackageamsmath
begindocument
beginalign
2 cosh t &= e^t \
&quad+ e^-t
endalign
enddocument
You can also use hspace
if you want a different length for the indentation.
answered Nov 17 '14 at 13:49
Ian ThompsonIan Thompson
32.1k379155
32.1k379155
3
Wouldn'tbeginalign 2 cosh t &= e^t \ &phantom= + e^-t endalign
be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.
– Niel de Beaudrap
Nov 17 '14 at 17:21
I'd say it's a matter of taste.
– Ian Thompson
Nov 18 '14 at 8:08
add a comment |
3
Wouldn'tbeginalign 2 cosh t &= e^t \ &phantom= + e^-t endalign
be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.
– Niel de Beaudrap
Nov 17 '14 at 17:21
I'd say it's a matter of taste.
– Ian Thompson
Nov 18 '14 at 8:08
3
3
Wouldn't
beginalign 2 cosh t &= e^t \ &phantom= + e^-t endalign
be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.– Niel de Beaudrap
Nov 17 '14 at 17:21
Wouldn't
beginalign 2 cosh t &= e^t \ &phantom= + e^-t endalign
be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.– Niel de Beaudrap
Nov 17 '14 at 17:21
I'd say it's a matter of taste.
– Ian Thompson
Nov 18 '14 at 8:08
I'd say it's a matter of taste.
– Ian Thompson
Nov 18 '14 at 8:08
add a comment |
I wouldn't try aligning the plus with e^t
, but if you insist, here's how.
documentclassarticle
usepackageamsmath
begindocument
noindent
The plus is flush with $e^t$ (I wouldn't recommend it):
beginalign
2cosh t =& e^t \
& negmedspace+ e^-t
endalign
The plus is moved right (better):
beginalign
2cosh t &= e^t \
&qquad+ e^-t
endalign
enddocument
With negmedspace
we kill the space at the left of the binary operation symbol.
However, align
is the wrong tool here:
documentclassarticle
usepackageamsmath
begindocument
beginequation
beginsplit
2cosh t &= e^t \
&qquad + e^-t
endsplit
endequation
add a comment |
I wouldn't try aligning the plus with e^t
, but if you insist, here's how.
documentclassarticle
usepackageamsmath
begindocument
noindent
The plus is flush with $e^t$ (I wouldn't recommend it):
beginalign
2cosh t =& e^t \
& negmedspace+ e^-t
endalign
The plus is moved right (better):
beginalign
2cosh t &= e^t \
&qquad+ e^-t
endalign
enddocument
With negmedspace
we kill the space at the left of the binary operation symbol.
However, align
is the wrong tool here:
documentclassarticle
usepackageamsmath
begindocument
beginequation
beginsplit
2cosh t &= e^t \
&qquad + e^-t
endsplit
endequation
add a comment |
I wouldn't try aligning the plus with e^t
, but if you insist, here's how.
documentclassarticle
usepackageamsmath
begindocument
noindent
The plus is flush with $e^t$ (I wouldn't recommend it):
beginalign
2cosh t =& e^t \
& negmedspace+ e^-t
endalign
The plus is moved right (better):
beginalign
2cosh t &= e^t \
&qquad+ e^-t
endalign
enddocument
With negmedspace
we kill the space at the left of the binary operation symbol.
However, align
is the wrong tool here:
documentclassarticle
usepackageamsmath
begindocument
beginequation
beginsplit
2cosh t &= e^t \
&qquad + e^-t
endsplit
endequation
I wouldn't try aligning the plus with e^t
, but if you insist, here's how.
documentclassarticle
usepackageamsmath
begindocument
noindent
The plus is flush with $e^t$ (I wouldn't recommend it):
beginalign
2cosh t =& e^t \
& negmedspace+ e^-t
endalign
The plus is moved right (better):
beginalign
2cosh t &= e^t \
&qquad+ e^-t
endalign
enddocument
With negmedspace
we kill the space at the left of the binary operation symbol.
However, align
is the wrong tool here:
documentclassarticle
usepackageamsmath
begindocument
beginequation
beginsplit
2cosh t &= e^t \
&qquad + e^-t
endsplit
endequation
answered Nov 17 '14 at 14:13
egregegreg
727k8819223231
727k8819223231
add a comment |
add a comment |
Suppose you wish to ensure that the two instances of e
are aligned vertically, while respecting the fact that a binary operator (+
) precedes the e
in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom
("horizonal phantom") statements. The one in the first row mimics the +
symbol (a binary operator) from the second row, and the hphantom
statement in the second row mimics the =
symbol (a relational operator) from the first row. The pairs are there to help TeX figure out which type of operator applies.
documentclassarticle
usepackageamsmath
setlengthtextwidth3in %% just for this example
begindocument
beginalign
2cosh t &= phantom+ mathrme^t \
&phantom= + mathrme^-t
endalign
enddocument
add a comment |
Suppose you wish to ensure that the two instances of e
are aligned vertically, while respecting the fact that a binary operator (+
) precedes the e
in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom
("horizonal phantom") statements. The one in the first row mimics the +
symbol (a binary operator) from the second row, and the hphantom
statement in the second row mimics the =
symbol (a relational operator) from the first row. The pairs are there to help TeX figure out which type of operator applies.
documentclassarticle
usepackageamsmath
setlengthtextwidth3in %% just for this example
begindocument
beginalign
2cosh t &= phantom+ mathrme^t \
&phantom= + mathrme^-t
endalign
enddocument
add a comment |
Suppose you wish to ensure that the two instances of e
are aligned vertically, while respecting the fact that a binary operator (+
) precedes the e
in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom
("horizonal phantom") statements. The one in the first row mimics the +
symbol (a binary operator) from the second row, and the hphantom
statement in the second row mimics the =
symbol (a relational operator) from the first row. The pairs are there to help TeX figure out which type of operator applies.
documentclassarticle
usepackageamsmath
setlengthtextwidth3in %% just for this example
begindocument
beginalign
2cosh t &= phantom+ mathrme^t \
&phantom= + mathrme^-t
endalign
enddocument
Suppose you wish to ensure that the two instances of e
are aligned vertically, while respecting the fact that a binary operator (+
) precedes the e
in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom
("horizonal phantom") statements. The one in the first row mimics the +
symbol (a binary operator) from the second row, and the hphantom
statement in the second row mimics the =
symbol (a relational operator) from the first row. The pairs are there to help TeX figure out which type of operator applies.
documentclassarticle
usepackageamsmath
setlengthtextwidth3in %% just for this example
begindocument
beginalign
2cosh t &= phantom+ mathrme^t \
&phantom= + mathrme^-t
endalign
enddocument
answered Nov 17 '14 at 14:03
MicoMico
283k31388775
283k31388775
add a comment |
add a comment |
You have placed the &
wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom
to indent the expression in the second line to get the correct alignment. (Notice the before
=
.)
documentclassarticle
usepackageamsmath
begindocument
beginalign
2cosh t
&= e^t \
&hphantom= + e^-t
endalign
enddocument
1
It is not wrong, one just have to be a bit more careful. Besides ` = &` is a lot short to type than&hphantom=
;-)
– daleif
Nov 17 '14 at 15:19
@daleif Good point. The reason why I usedhphantom
is that it's more 'universal'.
– Svend Tveskæg
Nov 17 '14 at 16:33
add a comment |
You have placed the &
wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom
to indent the expression in the second line to get the correct alignment. (Notice the before
=
.)
documentclassarticle
usepackageamsmath
begindocument
beginalign
2cosh t
&= e^t \
&hphantom= + e^-t
endalign
enddocument
1
It is not wrong, one just have to be a bit more careful. Besides ` = &` is a lot short to type than&hphantom=
;-)
– daleif
Nov 17 '14 at 15:19
@daleif Good point. The reason why I usedhphantom
is that it's more 'universal'.
– Svend Tveskæg
Nov 17 '14 at 16:33
add a comment |
You have placed the &
wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom
to indent the expression in the second line to get the correct alignment. (Notice the before
=
.)
documentclassarticle
usepackageamsmath
begindocument
beginalign
2cosh t
&= e^t \
&hphantom= + e^-t
endalign
enddocument
You have placed the &
wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom
to indent the expression in the second line to get the correct alignment. (Notice the before
=
.)
documentclassarticle
usepackageamsmath
begindocument
beginalign
2cosh t
&= e^t \
&hphantom= + e^-t
endalign
enddocument
edited Nov 17 '14 at 14:03
answered Nov 17 '14 at 13:51
Svend TveskægSvend Tveskæg
20.8k1052140
20.8k1052140
1
It is not wrong, one just have to be a bit more careful. Besides ` = &` is a lot short to type than&hphantom=
;-)
– daleif
Nov 17 '14 at 15:19
@daleif Good point. The reason why I usedhphantom
is that it's more 'universal'.
– Svend Tveskæg
Nov 17 '14 at 16:33
add a comment |
1
It is not wrong, one just have to be a bit more careful. Besides ` = &` is a lot short to type than&hphantom=
;-)
– daleif
Nov 17 '14 at 15:19
@daleif Good point. The reason why I usedhphantom
is that it's more 'universal'.
– Svend Tveskæg
Nov 17 '14 at 16:33
1
1
It is not wrong, one just have to be a bit more careful. Besides ` = &` is a lot short to type than
&hphantom=
;-)– daleif
Nov 17 '14 at 15:19
It is not wrong, one just have to be a bit more careful. Besides ` = &` is a lot short to type than
&hphantom=
;-)– daleif
Nov 17 '14 at 15:19
@daleif Good point. The reason why I used
hphantom
is that it's more 'universal'.– Svend Tveskæg
Nov 17 '14 at 16:33
@daleif Good point. The reason why I used
hphantom
is that it's more 'universal'.– Svend Tveskæg
Nov 17 '14 at 16:33
add a comment |
Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.
LaTeX encloses relation symbols with thick spaces ;
, and binary symbols with medium spaces :
. The symbols =
and +
in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:
2 cosh t & ; mathord= ; e^t \
& ; phantom= ; mathord+ : e^-t
A practical incarnation of the above is (see page 36 of l2kurz.pdf):
2 cosh t & = e^t \
& mathrelphantom= negmedspace + e^-t
First, we redeem the relation status of =
robbed by the phantom
command. Second, we insert an empty group telling LaTeX to interpret
+
as a binary rather than a prefix symbol; but this creates a spurious medium space :
that needs to be compensated.
New contributor
add a comment |
Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.
LaTeX encloses relation symbols with thick spaces ;
, and binary symbols with medium spaces :
. The symbols =
and +
in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:
2 cosh t & ; mathord= ; e^t \
& ; phantom= ; mathord+ : e^-t
A practical incarnation of the above is (see page 36 of l2kurz.pdf):
2 cosh t & = e^t \
& mathrelphantom= negmedspace + e^-t
First, we redeem the relation status of =
robbed by the phantom
command. Second, we insert an empty group telling LaTeX to interpret
+
as a binary rather than a prefix symbol; but this creates a spurious medium space :
that needs to be compensated.
New contributor
add a comment |
Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.
LaTeX encloses relation symbols with thick spaces ;
, and binary symbols with medium spaces :
. The symbols =
and +
in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:
2 cosh t & ; mathord= ; e^t \
& ; phantom= ; mathord+ : e^-t
A practical incarnation of the above is (see page 36 of l2kurz.pdf):
2 cosh t & = e^t \
& mathrelphantom= negmedspace + e^-t
First, we redeem the relation status of =
robbed by the phantom
command. Second, we insert an empty group telling LaTeX to interpret
+
as a binary rather than a prefix symbol; but this creates a spurious medium space :
that needs to be compensated.
New contributor
Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.
LaTeX encloses relation symbols with thick spaces ;
, and binary symbols with medium spaces :
. The symbols =
and +
in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:
2 cosh t & ; mathord= ; e^t \
& ; phantom= ; mathord+ : e^-t
A practical incarnation of the above is (see page 36 of l2kurz.pdf):
2 cosh t & = e^t \
& mathrelphantom= negmedspace + e^-t
First, we redeem the relation status of =
robbed by the phantom
command. Second, we insert an empty group telling LaTeX to interpret
+
as a binary rather than a prefix symbol; but this creates a spurious medium space :
that needs to be compensated.
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answered 11 mins ago
ChristophChristoph
1
1
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2
Welcome to TeX.SE! To get the correct spacing around the
=
sign, one must write&=
rather than=&
.– Mico
Nov 17 '14 at 13:50