How to use correctly dl with vectors using the diffcoeff package?
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How to use correctly dl with vectors using the diffcoeff package?
I am showing the following question about the use of differential dl in section six of the user guide diffcoeff.
- Why does not the command
dl vecxwork? - When dealing with the unknown
x, the numerical value betweendlandxindicates the horizontal space of that number in mu before the x. But I do not think that happens in (4) and (5). Is it possible via a command that allows me to usedl vectxin the "natural way"? That is, it works (6).
Minimal working example
documentclassarticle
usepackage[ISO]diffcoeff
begindocument
[
diffvecxvecy % (1) Works.
qquad
vecdl x % (2) Works.
quad
vecdl x % (3) Works.
quad
dl5vecx % (4) Works.
quad
dl0vecx % (5) Works.
quad
%dl vecx % (6) Do not work.
]
enddocument
Thanks in advance.
Please add the tag [diffcoeff] in the question.
math-mode macros
asked 41 secs ago
OromionOromion
10218
add a comment |
I am showing the following question about the use of differential dl in section six of the user guide diffcoeff.
- Why does not the command
dl vecxwork? - When dealing with the unknown
x, the numerical value betweendlandxindicates the horizontal space of that number in mu before the x. But I do not think that happens in (4) and (5). Is it possible via a command that allows me to usedl vectxin the "natural way"? That is, it works (6).
Minimal working example
documentclassarticle
usepackage[ISO]diffcoeff
begindocument
[
diffvecxvecy % (1) Works.
qquad
vecdl x % (2) Works.
quad
vecdl x % (3) Works.
quad
dl5vecx % (4) Works.
quad
dl0vecx % (5) Works.
quad
%dl vecx % (6) Do not work.
]
enddocument
Thanks in advance.
Please add the tag [diffcoeff] in the question.
math-mode macros
asked 41 secs ago
OromionOromion
10218
add a comment |
I am showing the following question about the use of differential dl in section six of the user guide diffcoeff.
- Why does not the command
dl vecxwork? - When dealing with the unknown
x, the numerical value betweendlandxindicates the horizontal space of that number in mu before the x. But I do not think that happens in (4) and (5). Is it possible via a command that allows me to usedl vectxin the "natural way"? That is, it works (6).
Minimal working example
documentclassarticle
usepackage[ISO]diffcoeff
begindocument
[
diffvecxvecy % (1) Works.
qquad
vecdl x % (2) Works.
quad
vecdl x % (3) Works.
quad
dl5vecx % (4) Works.
quad
dl0vecx % (5) Works.
quad
%dl vecx % (6) Do not work.
]
enddocument
Thanks in advance.
Please add the tag [diffcoeff] in the question.
math-mode macros
asked 41 secs ago
OromionOromion
10218
I am showing the following question about the use of differential dl in section six of the user guide diffcoeff.
- Why does not the command
dl vecxwork? - When dealing with the unknown
x, the numerical value betweendlandxindicates the horizontal space of that number in mu before the x. But I do not think that happens in (4) and (5). Is it possible via a command that allows me to usedl vectxin the "natural way"? That is, it works (6).
Minimal working example
documentclassarticle
usepackage[ISO]diffcoeff
begindocument
[
diffvecxvecy % (1) Works.
qquad
vecdl x % (2) Works.
quad
vecdl x % (3) Works.
quad
dl5vecx % (4) Works.
quad
dl0vecx % (5) Works.
quad
%dl vecx % (6) Do not work.
]
enddocument
Thanks in advance.
Please add the tag [diffcoeff] in the question.
math-mode macros
math-mode macros
asked 41 secs ago
OromionOromion
10218
asked 41 secs ago
OromionOromion
10218
asked 41 secs ago
OromionOromion
10218
asked 41 secs ago
OromionOromion
10218
asked 41 secs ago
OromionOromion
10218
10218
add a comment |
add a comment |
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