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How to use correctly dl with vectors using the diffcoeff package?

0

I am showing the following question about the use of differential dl in section six of the user guide diffcoeff.

• Why does not the commanddl vecx work?


• When dealing with the unknown x, the numerical value between dl and x indicates the horizontal space of that number in mu before the x. But I do not think that happens in (4) and (5). Is it possible via a command that allows me to use dl vectx in the "natural way"? That is, it works (6).

Minimal working example

documentclassarticle
usepackage[ISO]diffcoeff

begindocument

[
 diffvecxvecy % (1) Works.
 qquad
 vecdl x % (2) Works.
 quad
 vecdl x % (3) Works.
 quad
 dl5vecx % (4) Works.
 quad
 dl0vecx % (5) Works.
 quad
 %dl vecx % (6) Do not work.
]
enddocument

Thanks in advance.

Please add the tag [diffcoeff] in the question.

math-mode macros

share

asked 41 secs ago

OromionOromion

10218

add a comment | 

0

I am showing the following question about the use of differential dl in section six of the user guide diffcoeff.

• Why does not the commanddl vecx work?


• When dealing with the unknown x, the numerical value between dl and x indicates the horizontal space of that number in mu before the x. But I do not think that happens in (4) and (5). Is it possible via a command that allows me to use dl vectx in the "natural way"? That is, it works (6).

Minimal working example

documentclassarticle
usepackage[ISO]diffcoeff

begindocument

[
 diffvecxvecy % (1) Works.
 qquad
 vecdl x % (2) Works.
 quad
 vecdl x % (3) Works.
 quad
 dl5vecx % (4) Works.
 quad
 dl0vecx % (5) Works.
 quad
 %dl vecx % (6) Do not work.
]
enddocument

Thanks in advance.

Please add the tag [diffcoeff] in the question.

math-mode macros

share

asked 41 secs ago

OromionOromion

10218

add a comment | 

I am showing the following question about the use of differential dl in section six of the user guide diffcoeff.

• Why does not the commanddl vecx work?


• When dealing with the unknown x, the numerical value between dl and x indicates the horizontal space of that number in mu before the x. But I do not think that happens in (4) and (5). Is it possible via a command that allows me to use dl vectx in the "natural way"? That is, it works (6).

Minimal working example

documentclassarticle
usepackage[ISO]diffcoeff

begindocument

[
 diffvecxvecy % (1) Works.
 qquad
 vecdl x % (2) Works.
 quad
 vecdl x % (3) Works.
 quad
 dl5vecx % (4) Works.
 quad
 dl0vecx % (5) Works.
 quad
 %dl vecx % (6) Do not work.
]
enddocument

Thanks in advance.

Please add the tag [diffcoeff] in the question.

math-mode macros

share

asked 41 secs ago

OromionOromion

10218

documentclassarticle
usepackage[ISO]diffcoeff

begindocument

[
 diffvecxvecy % (1) Works.
 qquad
 vecdl x % (2) Works.
 quad
 vecdl x % (3) Works.
 quad
 dl5vecx % (4) Works.
 quad
 dl0vecx % (5) Works.
 quad
 %dl vecx % (6) Do not work.
]
enddocument

share

asked 41 secs ago

OromionOromion

10218

share

asked 41 secs ago

OromionOromion

10218

asked 41 secs ago

OromionOromion

10218

asked 41 secs ago

OromionOromion

10218