Recall an hypothesis Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Making a list of hypothesis and references to the hypothesisIncorrect hypothesis counterNew example environment, with symbol at the endRestart hypothesis counter in new chapterRecall a theorem in a different section of a chapteramsmath aligned environment: correct positioning of equation number on the last line with tbtagsChanging numbers of equations
Why did the Falcon Heavy center core fall off the ASDS OCISLY barge?
A coin, having probability p of landing heads and probability of q=(1-p) of landing on heads.
Storing hydrofluoric acid before the invention of plastics
Denied boarding although I have proper visa and documentation. To whom should I make a complaint?
Why didn't this character "real die" when they blew their stack out in Altered Carbon?
Why am I getting the error "non-boolean type specified in a context where a condition is expected" for this request?
List of Python versions
When do you get frequent flier miles - when you buy, or when you fly?
Identifying polygons that intersect with another layer using QGIS?
Echoing a tail command produces unexpected output?
Are two submodules (where one is contained in the other) isomorphic if their quotientmodules are isomorphic?
What is the meaning of the new sigil in Game of Thrones Season 8 intro?
porting install scripts : can rpm replace apt?
prime numbers and expressing non-prime numbers
Generate an RGB colour grid
Withdrew £2800, but only £2000 shows as withdrawn on online banking; what are my obligations?
51k Euros annually for a family of 4 in Berlin: Is it enough?
Resolving to minmaj7
English words in a non-english sci-fi novel
What exactly is a "Meth" in Altered Carbon?
Should I use a zero-interest credit card for a large one-time purchase?
2001: A Space Odyssey's use of the song "Daisy Bell" (Bicycle Built for Two); life imitates art or vice-versa?
Why did the rest of the Eastern Bloc not invade Yugoslavia?
Why are there no cargo aircraft with "flying wing" design?
Recall an hypothesis
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Making a list of hypothesis and references to the hypothesisIncorrect hypothesis counterNew example environment, with symbol at the endRestart hypothesis counter in new chapterRecall a theorem in a different section of a chapteramsmath aligned environment: correct positioning of equation number on the last line with tbtagsChanging numbers of equations
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheoremhypothesisHypothesis
beginhypothesis %Hyp 1
beginjustify
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
endjustifypar
endhypothesis
beginhypothesis %Hyp 2
beginjustify
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
endjustifypar
endhypothesis
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
beginhypothesis %Hyp1
beginequation
x
endequationpar
endhypothesis
beginhypothesis %Hyp2
beginequation
xtimes (-1)
endequationpar
endhypothesis
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
bumped to the homepage by Community♦ 4 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheoremhypothesisHypothesis
beginhypothesis %Hyp 1
beginjustify
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
endjustifypar
endhypothesis
beginhypothesis %Hyp 2
beginjustify
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
endjustifypar
endhypothesis
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
beginhypothesis %Hyp1
beginequation
x
endequationpar
endhypothesis
beginhypothesis %Hyp2
beginequation
xtimes (-1)
endequationpar
endhypothesis
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
bumped to the homepage by Community♦ 4 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheoremhypothesisHypothesis
beginhypothesis %Hyp 1
beginjustify
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
endjustifypar
endhypothesis
beginhypothesis %Hyp 2
beginjustify
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
endjustifypar
endhypothesis
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
beginhypothesis %Hyp1
beginequation
x
endequationpar
endhypothesis
beginhypothesis %Hyp2
beginequation
xtimes (-1)
endequationpar
endhypothesis
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheoremhypothesisHypothesis
beginhypothesis %Hyp 1
beginjustify
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
endjustifypar
endhypothesis
beginhypothesis %Hyp 2
beginjustify
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
endjustifypar
endhypothesis
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
beginhypothesis %Hyp1
beginequation
x
endequationpar
endhypothesis
beginhypothesis %Hyp2
beginequation
xtimes (-1)
endequationpar
endhypothesis
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
numbering packages theorems text ntheorem
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
edited Jun 20 '18 at 10:59
Rufyyyyy
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
62
bumped to the homepage by Community♦ 4 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 4 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclassarticle
usepackageamsthm, amsmath
newcounterhypcounter
newtheoremhypothesisHypothesis
newcommandfirsthyp[1]
setcounterhypcountervaluehypothesis % save what number we're at
setcounterhypothesis0 % so that the hypothesis is numbered 1
beginhypothesis
My first hypothesis states some stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter % rewrite that number back into counter
newcommandsecondhyp[1]
setcounterhypcountervaluehypothesis
setcounterhypothesis1 % so that the hypothesis is numbered 2
beginhypothesis
My second hypothesis states some other stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter
begindocument
setcounterhypothesis2 % so that a hypotheses afterwards will begin at 3
firsthypRE>RM land RF>RM lor RE<RM land RF<RM implies
secondhypRE>RM land RF<RM lor RE<RM land RF>RM implies
beginhypothesis
Another hypothesis will be numbered with the next number, $3$.
beginequation
textEquation numbering continue as normal
endequation
endhypothesis
firsthypx
secondhypxtimes (-1)
enddocument
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
I thinksetcounterhypothesisn(n= previous value) before calling the hypothesis and asetcounterhypothesisx(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironmentcommand with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "85"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f437181%2frecall-an-hypothesis%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclassarticle
usepackageamsthm, amsmath
newcounterhypcounter
newtheoremhypothesisHypothesis
newcommandfirsthyp[1]
setcounterhypcountervaluehypothesis % save what number we're at
setcounterhypothesis0 % so that the hypothesis is numbered 1
beginhypothesis
My first hypothesis states some stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter % rewrite that number back into counter
newcommandsecondhyp[1]
setcounterhypcountervaluehypothesis
setcounterhypothesis1 % so that the hypothesis is numbered 2
beginhypothesis
My second hypothesis states some other stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter
begindocument
setcounterhypothesis2 % so that a hypotheses afterwards will begin at 3
firsthypRE>RM land RF>RM lor RE<RM land RF<RM implies
secondhypRE>RM land RF<RM lor RE<RM land RF>RM implies
beginhypothesis
Another hypothesis will be numbered with the next number, $3$.
beginequation
textEquation numbering continue as normal
endequation
endhypothesis
firsthypx
secondhypxtimes (-1)
enddocument
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
I thinksetcounterhypothesisn(n= previous value) before calling the hypothesis and asetcounterhypothesisx(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironmentcommand with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclassarticle
usepackageamsthm, amsmath
newcounterhypcounter
newtheoremhypothesisHypothesis
newcommandfirsthyp[1]
setcounterhypcountervaluehypothesis % save what number we're at
setcounterhypothesis0 % so that the hypothesis is numbered 1
beginhypothesis
My first hypothesis states some stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter % rewrite that number back into counter
newcommandsecondhyp[1]
setcounterhypcountervaluehypothesis
setcounterhypothesis1 % so that the hypothesis is numbered 2
beginhypothesis
My second hypothesis states some other stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter
begindocument
setcounterhypothesis2 % so that a hypotheses afterwards will begin at 3
firsthypRE>RM land RF>RM lor RE<RM land RF<RM implies
secondhypRE>RM land RF<RM lor RE<RM land RF>RM implies
beginhypothesis
Another hypothesis will be numbered with the next number, $3$.
beginequation
textEquation numbering continue as normal
endequation
endhypothesis
firsthypx
secondhypxtimes (-1)
enddocument
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
I thinksetcounterhypothesisn(n= previous value) before calling the hypothesis and asetcounterhypothesisx(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironmentcommand with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclassarticle
usepackageamsthm, amsmath
newcounterhypcounter
newtheoremhypothesisHypothesis
newcommandfirsthyp[1]
setcounterhypcountervaluehypothesis % save what number we're at
setcounterhypothesis0 % so that the hypothesis is numbered 1
beginhypothesis
My first hypothesis states some stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter % rewrite that number back into counter
newcommandsecondhyp[1]
setcounterhypcountervaluehypothesis
setcounterhypothesis1 % so that the hypothesis is numbered 2
beginhypothesis
My second hypothesis states some other stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter
begindocument
setcounterhypothesis2 % so that a hypotheses afterwards will begin at 3
firsthypRE>RM land RF>RM lor RE<RM land RF<RM implies
secondhypRE>RM land RF<RM lor RE<RM land RF>RM implies
beginhypothesis
Another hypothesis will be numbered with the next number, $3$.
beginequation
textEquation numbering continue as normal
endequation
endhypothesis
firsthypx
secondhypxtimes (-1)
enddocument
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclassarticle
usepackageamsthm, amsmath
newcounterhypcounter
newtheoremhypothesisHypothesis
newcommandfirsthyp[1]
setcounterhypcountervaluehypothesis % save what number we're at
setcounterhypothesis0 % so that the hypothesis is numbered 1
beginhypothesis
My first hypothesis states some stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter % rewrite that number back into counter
newcommandsecondhyp[1]
setcounterhypcountervaluehypothesis
setcounterhypothesis1 % so that the hypothesis is numbered 2
beginhypothesis
My second hypothesis states some other stuff
beginequation #1 endequation
endhypothesis
setcounterhypothesisvaluehypcounter
begindocument
setcounterhypothesis2 % so that a hypotheses afterwards will begin at 3
firsthypRE>RM land RF>RM lor RE<RM land RF<RM implies
secondhypRE>RM land RF<RM lor RE<RM land RF>RM implies
beginhypothesis
Another hypothesis will be numbered with the next number, $3$.
beginequation
textEquation numbering continue as normal
endequation
endhypothesis
firsthypx
secondhypxtimes (-1)
enddocument
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
72727
I thinksetcounterhypothesisn(n= previous value) before calling the hypothesis and asetcounterhypothesisx(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironmentcommand with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
I thinksetcounterhypothesisn(n= previous value) before calling the hypothesis and asetcounterhypothesisx(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironmentcommand with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
I think
setcounterhypothesisn (n= previous value) before calling the hypothesis and a setcounterhypothesisx (x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in a newenvironment command with possibly an optional argument... Seems too complicated to me– koleygr
Sep 19 '18 at 1:09
I think
setcounterhypothesisn (n= previous value) before calling the hypothesis and a setcounterhypothesisx (x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in a newenvironment command with possibly an optional argument... Seems too complicated to me– koleygr
Sep 19 '18 at 1:09
add a comment |
Thanks for contributing an answer to TeX - LaTeX Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f437181%2frecall-an-hypothesis%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
