Tabular environment - text vertically positions itself by bottom of tikz picture in adjacent cellText positiong in cell (tabular)Vertically center text in a specific cellParagraph column in tabular working only in the first columnAligning text and a tikZ picture verticallytabular can't vertically align the cell to the topExhaustive Information about text alignment in TabularVertically aligning tabular cell contents with respect to one anotherCenter tikz vertically inside tabular cellMake text next to picture vertically centeredSuppressing all bottom padding of tabular cell
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Tabular environment - text vertically positions itself by bottom of tikz picture in adjacent cell
Text positiong in cell (tabular)Vertically center text in a specific cellParagraph column in tabular working only in the first columnAligning text and a tikZ picture verticallytabular can't vertically align the cell to the topExhaustive Information about text alignment in TabularVertically aligning tabular cell contents with respect to one anotherCenter tikz vertically inside tabular cellMake text next to picture vertically centeredSuppressing all bottom padding of tabular cell
I would like to get my text (actually a matrix) to vertically center itself in its cell. Instead, it centers itself based on where the bottom of the tikz picture in the adjacent cell lies. This adds unnecessary height to a table I would like to eliminate. Is there any way to force the text column to align with the center of the tikz picture or to ignore the tikz picture entirely?
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
tables vertical-alignment
asked 2 hours ago
AlexJAlexJ
384
add a comment |
I would like to get my text (actually a matrix) to vertically center itself in its cell. Instead, it centers itself based on where the bottom of the tikz picture in the adjacent cell lies. This adds unnecessary height to a table I would like to eliminate. Is there any way to force the text column to align with the center of the tikz picture or to ignore the tikz picture entirely?
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
tables vertical-alignment
asked 2 hours ago
AlexJAlexJ
384
add a comment |
I would like to get my text (actually a matrix) to vertically center itself in its cell. Instead, it centers itself based on where the bottom of the tikz picture in the adjacent cell lies. This adds unnecessary height to a table I would like to eliminate. Is there any way to force the text column to align with the center of the tikz picture or to ignore the tikz picture entirely?
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
tables vertical-alignment
asked 2 hours ago
AlexJAlexJ
384
I would like to get my text (actually a matrix) to vertically center itself in its cell. Instead, it centers itself based on where the bottom of the tikz picture in the adjacent cell lies. This adds unnecessary height to a table I would like to eliminate. Is there any way to force the text column to align with the center of the tikz picture or to ignore the tikz picture entirely?
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
tables vertical-alignment
tables vertical-alignment
asked 2 hours ago
AlexJAlexJ
384
asked 2 hours ago
AlexJAlexJ
384
asked 2 hours ago
AlexJAlexJ
384
asked 2 hours ago
AlexJAlexJ
384
asked 2 hours ago
AlexJAlexJ
384
384
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You can use baseline=(current bounding box.center) to achieve the desired alignment as shown in the following code:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
As the border of the image now overlaps with the horizontal lines, you might want to add some extra vertical space (as done here using the cellspace package):
documentclass[12pt]article
usepackageamsmath
usepackagecellspace
setlengthcellspacetoplimit6pt
setlengthcellspacebottomlimit6pt
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular Sc hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
leandriisleandriis
9,5451530
add a comment |
A fix with an optional argument for the baseline of the tikzpicture:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic[1][-17pt]
centering
begintikzpicture[x=1cm,y=1cm,baseline=#1]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture%
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic[-25pt] & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
koleygrkoleygr
12.1k11038
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use baseline=(current bounding box.center) to achieve the desired alignment as shown in the following code:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
As the border of the image now overlaps with the horizontal lines, you might want to add some extra vertical space (as done here using the cellspace package):
documentclass[12pt]article
usepackageamsmath
usepackagecellspace
setlengthcellspacetoplimit6pt
setlengthcellspacebottomlimit6pt
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular Sc hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
leandriisleandriis
9,5451530
add a comment |
You can use baseline=(current bounding box.center) to achieve the desired alignment as shown in the following code:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
As the border of the image now overlaps with the horizontal lines, you might want to add some extra vertical space (as done here using the cellspace package):
documentclass[12pt]article
usepackageamsmath
usepackagecellspace
setlengthcellspacetoplimit6pt
setlengthcellspacebottomlimit6pt
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular Sc hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
leandriisleandriis
9,5451530
add a comment |
You can use baseline=(current bounding box.center) to achieve the desired alignment as shown in the following code:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
As the border of the image now overlaps with the horizontal lines, you might want to add some extra vertical space (as done here using the cellspace package):
documentclass[12pt]article
usepackageamsmath
usepackagecellspace
setlengthcellspacetoplimit6pt
setlengthcellspacebottomlimit6pt
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular Sc hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
leandriisleandriis
9,5451530
You can use baseline=(current bounding box.center) to achieve the desired alignment as shown in the following code:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
As the border of the image now overlaps with the horizontal lines, you might want to add some extra vertical space (as done here using the cellspace package):
documentclass[12pt]article
usepackageamsmath
usepackagecellspace
setlengthcellspacetoplimit6pt
setlengthcellspacebottomlimit6pt
usepackagetikz
newcommandpic
centering
begintikzpicture[x=1cm,y=1cm,baseline=(current bounding box.center)]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture
begindocument
begintabular Sc hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
leandriisleandriis
9,5451530
edited 2 hours ago
answered 2 hours ago
leandriisleandriis
9,5451530
answered 2 hours ago
leandriisleandriis
9,5451530
answered 2 hours ago
leandriisleandriis
9,5451530
9,5451530
add a comment |
add a comment |
A fix with an optional argument for the baseline of the tikzpicture:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic[1][-17pt]
centering
begintikzpicture[x=1cm,y=1cm,baseline=#1]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture%
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic[-25pt] & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
koleygrkoleygr
12.1k11038
add a comment |
A fix with an optional argument for the baseline of the tikzpicture:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic[1][-17pt]
centering
begintikzpicture[x=1cm,y=1cm,baseline=#1]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture%
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic[-25pt] & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
koleygrkoleygr
12.1k11038
add a comment |
A fix with an optional argument for the baseline of the tikzpicture:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic[1][-17pt]
centering
begintikzpicture[x=1cm,y=1cm,baseline=#1]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture%
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic[-25pt] & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
koleygrkoleygr
12.1k11038
A fix with an optional argument for the baseline of the tikzpicture:
documentclass[12pt]article
usepackageamsmath
usepackagetikz
newcommandpic[1][-17pt]
centering
begintikzpicture[x=1cm,y=1cm,baseline=#1]
useasboundingbox (0,.5) rectangle (3, -2);
draw (current bounding box.north east) -- (current bounding box.north west) -- (current bounding box.south west) -- (current bounding box.south east) -- cycle;
endtikzpicture%
begindocument
begintabular c hline
Initial Pic & Final Pic & U \ hline
pic & pic & \ hline
pic & pic & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
pic[-25pt] & that &
$textU = .5 beginbmatrix
0 & 0 & 0 & 0 \
0 & 0 & 0 & 0 \
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
this & that & $textU = beginbmatrix
1 & i & 1 & -i \
-i & 1 & i & 1 \
1 & -i & 1 & i \
i & 1 & -i & 1 endbmatrix$ \ hline
endtabular
enddocument
answered 2 hours ago
koleygrkoleygr
12.1k11038
answered 2 hours ago
koleygrkoleygr
12.1k11038
answered 2 hours ago
koleygrkoleygr
12.1k11038
answered 2 hours ago
koleygrkoleygr
12.1k11038
12.1k11038
add a comment |
add a comment |
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